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Force • Work • Power Calculator

Calculate force (F = m·a), work (W = F·d·cos θ), and power (P = W/t). Analyze inclined planes with friction and compute work from variable forces.

F = m × aW = F × d × cos(θ)P = W / t

Quick Answer

Force (N) = mass × acceleration — any push or pull that changes motion.

Work (J) = force × distance × cos(angle) — energy transferred when moving an object.

Power (W) = work ÷ time — how fast work is done.

Show more details & example

For example, pushing a 10 kg box with 2 m/s² acceleration requires 20 N of force. Moving that box 5 meters horizontally does 100 J of work (20 N × 5 m × cos(0°)). If done in 2 seconds, your power output is 50 W.

Example: Lifting a Box

Lifting a 20 kg box to a 1.5 m high shelf against gravity (9.8 m/s²):

  • Force: 20 kg × 9.8 m/s² = 196 N
  • Work: 196 N × 1.5 m = 294 J
  • Power: 294 J ÷ 3 s = 98 W
Calculator

Force • Work • Power Calculator

Calculate force, work, power, and analyze inclined planes with friction.


Ready to Calculate

Select a mode and enter your values to calculate force, work, or power. Results will appear here.

Last Updated: November 20, 2025

Understanding Force, Work & Power

The Force • Work • Power Calculator helps you analyze how physical effort translates into mechanical energy and rate of performance. It applies classic physics laws that describe motion, energy transfer, and system efficiency—essential for engineering, sports science, automotive design, and physics education.

Core Formulas

  • Force (F): F = m × a, where m is mass (kg or lbm) and a is acceleration (m/s² or ft/s²). Force is the push or pull that causes an object to change its velocity. Measured in newtons (N) in SI units or pounds-force (lbf) in Imperial units. Newton's Second Law: 1 N = 1 kg·m/s².
  • Work (W): W = F × d × cos(θ), where F is force, d is displacement (distance moved), and θ is the angle between the force vector and the direction of motion. Work represents energy transferred when a force moves an object. Only the component of force parallel to motion contributes to work. Measured in joules (J) in SI or foot-pounds (ft·lbf) in Imperial units. 1 J = 1 N·m.
  • Power (P): P = W/t (work per unit time) or P = F × v (force times velocity), where t is time and v is velocity. Power is the rate of doing work—how quickly energy is transferred or converted. Measured in watts (W) where 1 W = 1 J/s, or horsepower (hp) where 1 hp ≈ 745.7 W. Higher power means faster energy transfer.

Related Concepts

  • Inclined Plane with Friction: Calculates the force required to move a mass along a slope, accounting for both gravitational resistance (component of weight parallel to incline) and frictional resistance (μ × normal force). The normal force N = mg cos(α) is perpendicular to the surface, and friction force F_friction = μN opposes motion. Net required force = mg sin(α) + μmg cos(α), where α is the incline angle.
  • Variable Force Integration: When force varies with displacement (e.g., spring force F = kx, or non-uniform applied forces), work cannot be calculated with simple multiplication. Instead, use numerical integration: W = ∫F(x)dx over the displacement range. The calculator uses trapezoidal or Simpson's rule to approximate the area under the force vs. displacement curve.
  • Unit Conversion: Supports both SI (metric) and Imperial (US customary) systems. Automatically converts between N ↔ lbf (1 lbf ≈ 4.448 N), J ↔ ft·lbf (1 J ≈ 0.7376 ft·lbf), and W ↔ hp (1 hp = 745.7 W). Ensures consistency across mass (kg ↔ lbm), distance (m ↔ ft), and time (s) units.

Understanding these principles allows you to design motors, optimize athletic performance, calculate engine output, and predict energy requirements for mechanical systems.

How to Use the Calculator

This calculator provides multiple modes to solve different physics problems involving force, work, and power. Follow these steps:

  1. Select Calculation Mode: Choose the physics quantity you want to calculate:
    • Force (F = m × a): Enter mass (kg or lbm) and acceleration (m/s² or ft/s²) to calculate the force in newtons or pounds-force. Use this for Newton's Second Law problems.
    • Work (W = F × d × cos θ): Enter force, displacement (distance moved), and angle between force and motion. If force is applied in the direction of motion, use θ = 0°. For perpendicular force, use θ = 90° (which gives W = 0).
    • Power (P = W/t or F × v): Choose between two methods: (1) work-based: enter total work done and time elapsed, or (2) force-velocity based: enter force and velocity. Both give power in watts or horsepower.
    • Inclined Plane (with friction): Input mass, incline angle (degrees), gravitational acceleration (default 9.81 m/s² on Earth), and friction coefficient μ (typically 0.1-0.5 for most surfaces). Calculator computes normal force, friction force, net force required, work against gravity and friction, and total power if velocity is provided.
    • Variable Force Integration: Enter multiple (force, displacement) data points representing how force changes with position. The calculator numerically integrates to find total work done using trapezoidal approximation: W ≈ Σ[(Fi + Fi+1)/2 × (xi+1 - xi)].
  2. Choose Unit System: Select between:
    • SI (Metric): kg, m, s, N (newtons), J (joules), W (watts)
    • Imperial (US Customary): lbm (pounds-mass), ft (feet), s, lbf (pounds-force), ft·lbf, hp (horsepower)
    All inputs and outputs will follow the selected system. Conversions are handled automatically.
  3. Adjust Settings: Configure output preferences:
    • Decimal Precision: Choose number of decimal places (0-8) for rounding results.
    • Display Format: Select standard notation (e.g., 1234.56), scientific notation (e.g., 1.23e+3), or engineering notation (powers of 1000).
    • Show Steps: Enable to see detailed calculation breakdowns, intermediate values, formulas used, and visual diagrams explaining force components.
  4. Click "Calculate": View comprehensive results including:
    • Calculated force, work, or power with units
    • Component breakdowns (e.g., parallel force, normal force, friction force for inclined planes)
    • Step-by-step calculations (if enabled) showing formula substitution and intermediate steps
    • Interactive graphs: Force vs. Displacement, Work vs. Angle, Power vs. Time, or Force components diagram
    • Equivalent values in both SI and Imperial units for easy comparison
    • Physical interpretation and practical context for the calculated values

Pro Tip: When the force varies across distance (e.g., spring compression, variable drag, or non-uniform applied forces), use Variable Force Integration mode for accurate work calculations. Constant force assumptions can lead to significant errors in these scenarios.

Real-World Applications

  • Engineering & Mechanics: Design motors, lifts, elevators, and braking systems by calculating required forces and power ratings. Determine motor specifications (torque, horsepower) needed to move loads at desired speeds. Analyze pulley systems, gear trains, and hydraulic actuators. Example: Calculate the motor power required to lift a 500 kg elevator at 2 m/s: P = mgv = 500 × 9.81 × 2 ≈ 9810 W ≈ 13.1 hp.
  • Sports Science: Analyze athlete output, mechanical efficiency, and force generation in activities like sprinting, cycling, weightlifting, and jumping. Measure power output during exercises to optimize training intensity. Calculate work done during repetitive motions. Example: A cyclist exerting 200 N of force while traveling at 10 m/s generates P = Fv = 200 × 10 = 2000 W = 2.68 hp.
  • Automotive Engineering: Calculate engine horsepower from torque and RPM, analyze traction forces during acceleration, estimate braking distances from deceleration forces, and design transmission systems. Determine fuel efficiency based on work done against drag and friction. Example: An engine producing 300 hp at 5000 RPM delivers torque τ = P/(2πω) where ω is angular velocity in rad/s.
  • Physics Education: Demonstrate fundamental relationships between force, energy, mass, and velocity. Visualize how angle affects work (cos θ factor), understand energy conservation principles, and explore the difference between force (instantaneous) and work/power (energy-based). Use interactive graphs to build intuition about mechanical systems.
  • Construction & Material Handling: Estimate effort required to lift or move heavy loads using cranes, forklifts, and conveyor systems. Calculate work done against gravity when hoisting materials vertically. Design ramps and inclined planes to reduce required force (trading force for distance). Account for friction losses in cable systems and pulleys. Example: Moving a 1000 kg load up a 30° ramp with μ = 0.3 requires F = mg(sin 30° + 0.3 cos 30°) ≈ 7458 N.
  • Energy Systems & Renewable Power: Analyze wind turbine power output from wind force and blade velocity, calculate hydroelectric potential from water flow and height, estimate solar panel support structure forces from wind loads, and optimize energy conversion efficiency in mechanical systems.

Remember: Always verify that units are consistent before calculating. Mixing SI and Imperial units without proper conversion will produce incorrect results. The calculator handles conversions automatically when you select a unit system.

Understanding Your Results

The calculator presents results with detailed explanations and unit conversions. Here's how to interpret each output:

QuantitySymbolUnit (SI)Description
ForceFN (newton)Push or pull on an object. 1 N accelerates 1 kg at 1 m/s². Causes changes in motion (acceleration or deceleration).
WorkWJ (joule)Energy transferred by force over distance. 1 J = 1 N·m. Only force component parallel to motion does work. W = 0 if force is perpendicular to motion.
PowerPW (watt)Rate of doing work (energy per time). 1 W = 1 J/s. Higher power = faster energy transfer. 1 hp = 745.7 W (common in automotive contexts).
Angleθdegrees or radDirection of force relative to motion. θ = 0° means force and motion aligned (maximum work). θ = 90° means perpendicular (zero work). W = Fd cos(θ).
Friction CoefficientμDimensionless resistance between surfaces. Typical values: ice ~0.05, wood on wood ~0.4, rubber on concrete ~0.7. Friction force F_f = μN.
Normal ForceNN (newton)Reaction force perpendicular to surface. On horizontal surface: N = mg. On incline: N = mg cos(α). Determines friction magnitude.
Required ForceFreqN (newton)Net force needed to move mass on incline. F_req = mg sin(α) + μmg cos(α). Includes both gravitational and frictional resistance.
Work (Variable Force)WtotalJ (joule)Total energy via numerical integration when force varies with displacement. W ≈ Σ[(Fi + Fi+1)/2 × Δx]. More accurate than assuming constant force.

Outputs Display:

  • Both SI and Imperial Equivalents: Results show values in both unit systems (e.g., "245 N (55.1 lbf)") for easy reference and verification.
  • Component Diagrams: For inclined planes, visualize normal force (perpendicular to surface), friction force (opposing motion), weight component parallel to incline, and net required force.
  • Force vs. Displacement Graphs: For variable force problems, see how force changes with position and the area under the curve representing total work.
  • Work vs. Angle Plots: Visualize how work decreases as angle increases (cos θ relationship), reaching zero at 90° when force is perpendicular to motion.
  • Step-by-Step Calculations: When enabled, shows formula substitution, unit conversions, intermediate values, and final results with explanations at each step.

Limitations & Assumptions

• Constant Force Assumption: Basic calculations assume force remains constant throughout the motion. Variable forces (such as springs, air resistance, or changing applied force) require integration methods or numerical approaches not fully modeled in simple work calculations.

• Rigid Body Approximation: Objects are treated as perfectly rigid with no deformation. Real materials compress, stretch, and absorb energy during force application, which affects the actual work done and power transmitted.

• Idealized Friction Model: Friction calculations use constant coefficients (Coulomb friction model). Real friction depends on velocity, surface conditions, temperature, and contact area variations that can cause significant deviations from calculated values.

• No Energy Losses to Heat or Sound: Power efficiency calculations may not account for all real-world losses including heat generation, vibration, sound energy, and material fatigue that reduce the useful work output in practical systems.

Important Note: This calculator is strictly for educational and informational purposes only. It demonstrates fundamental force, work, and power principles for learning. Engineering applications requiring motor sizing, structural analysis, or machine design need comprehensive analysis accounting for dynamic loads and efficiency factors.

Sources & References

The formulas and principles used in this calculator are based on established physics principles from authoritative sources:

  • Halliday, D., Resnick, R., & Walker, J. (2018). Fundamentals of Physics (11th ed.). Wiley. — Chapters on force, work, energy, and power provide the foundational equations F = ma, W = Fd cos(θ), and P = W/t.
  • Serway, R. A., & Jewett, J. W. (2018). Physics for Scientists and Engineers (10th ed.). Cengage Learning. — Comprehensive coverage of Newton's laws, work-energy theorem, and power calculations.
  • NIST Reference on Constants, Units, and Uncertaintyphysics.nist.gov/cuu/Units/ — Standard definitions for SI units including newton, joule, and watt.
  • OpenStax College Physicsopenstax.org — Free, peer-reviewed textbook covering work, energy, and power concepts (Chapters 7-8).
  • HyperPhysicshyperphysics.phy-astr.gsu.edu — Georgia State University's physics reference for work, energy, and power relationships.
  • The Physics Classroomphysicsclassroom.com — Educational resource explaining work, energy, and power with interactive examples.

Note: This calculator implements standard physics formulas for educational purposes. For engineering applications requiring high precision, consult professional engineering references and standards.

Frequently Asked Questions

Common questions about force, work, power, angles, friction, and variable force integration.

What is the difference between force, work, and power?

Force is a push or pull measured in newtons (N), defined by F = m × a where m is mass and a is acceleration. Force causes objects to change their state of motion but doesn't necessarily involve energy transfer. Work is energy transferred when a force moves an object over a distance, calculated as W = F × d × cos(θ), measured in joules (J). Work requires both force and displacement—if an object doesn't move, no work is done regardless of force applied (e.g., pushing against a wall). Power is the rate of doing work, measured in watts (W) or horsepower (hp), calculated as P = W/t (work per unit time) or P = F × v (force times velocity). Power indicates how quickly energy is transferred—a 100 W motor does the same work as a 1000 W motor, just 10 times slower. In summary: Force is the cause, work is the energy transferred, and power is how fast that transfer happens.

Why does angle matter in work calculations?

Only the component of force that acts in the direction of motion contributes to work. The formula W = F × d × cos(θ) includes the cosine factor to account for this directional alignment. When force is applied at an angle θ to the direction of motion, we decompose the force into two components: F_parallel = F cos(θ) (in the direction of motion) and F_perpendicular = F sin(θ) (perpendicular to motion). Only F_parallel does work because work involves moving an object in the direction of force. Examples: (1) θ = 0° (force aligned with motion): cos(0°) = 1, so W = Fd (maximum work). (2) θ = 90° (force perpendicular to motion): cos(90°) = 0, so W = 0 (no work, like normal force when sliding horizontally). (3) θ = 180° (force opposite to motion): cos(180°) = -1, so W = -Fd (negative work, removing energy from the system, like friction). This principle explains why pulling a wagon at an angle is less efficient than pulling horizontally—only part of your force contributes to forward motion.

How do I convert between horsepower and watts?

Horsepower (hp) and watts (W) both measure power but use different unit systems. The conversion factor is: 1 horsepower = 745.7 watts (approximately). To convert: hp × 745.7 = watts, or watts ÷ 745.7 = hp. Examples: (1) A 200 hp car engine produces 200 × 745.7 ≈ 149,140 W ≈ 149 kW. (2) A 2000 W (2 kW) electric motor is equivalent to 2000 ÷ 745.7 ≈ 2.68 hp. Historical note: Horsepower was defined by James Watt in the 18th century as the power output of a typical draft horse—approximately 33,000 foot-pounds per minute. Today, mechanical horsepower (hp_I) = 745.7 W, while metric horsepower (PS, CV, or hp_M) ≈ 735.5 W, and electrical horsepower ≈ 746 W. Always verify which horsepower definition is being used in automotive or industrial contexts. In physics and engineering, watts are preferred because they integrate naturally with SI units (1 W = 1 J/s = 1 N·m/s).

What is an inclined plane and how does friction affect it?

An inclined plane is a flat surface tilted at an angle α to the horizontal, used to lift or move objects with reduced force compared to vertical lifting. It's one of the six classical simple machines. The gravitational force on an object (weight W = mg) can be decomposed into two components: (1) W_parallel = mg sin(α), acting down the slope, and (2) W_perpendicular = mg cos(α), pressing into the surface (creating normal force N = mg cos(α)). Without friction, the force required to push an object up the incline is F = mg sin(α). With friction, an additional resistance F_friction = μN = μmg cos(α) opposes motion, where μ is the friction coefficient. The total required force becomes F_total = mg sin(α) + μmg cos(α) = mg(sin α + μ cos α). Friction increases the effort needed but provides stability—preventing objects from sliding down unintentionally. Trade-off: Inclined planes reduce force requirements (compared to lifting vertically) but increase the distance traveled. Work done remains approximately the same: W_vertical = mgh (lifting straight up) vs. W_incline = F_total × d ≈ mgh + friction losses. Applications: ramps, roads in mountains, screws, wedges.

When should I use variable force integration?

Use variable force integration when the applied force changes with displacement (position), making simple multiplication W = F × d inaccurate. This occurs in several scenarios: (1) Springs and elastic systems: Force increases linearly with compression/extension (Hooke's Law: F = kx). Work done compressing a spring: W = ∫₀ˣ kx dx = ½kx². Simple F × d would overestimate. (2) Gravity over large distances: Gravitational force F = GMm/r² decreases with distance r from a massive object. For satellite launches, integration accounts for changing force. (3) Variable friction or drag: Friction changing with surface conditions, or air resistance increasing with velocity (F_drag ∝ v²). (4) Non-uniform applied forces: Manually pushing an object with varying effort, or engine force that changes during acceleration. (5) Experimental data: When you have measured force vs. position data points and need to find total work. The calculator uses numerical integration (trapezoidal rule): W ≈ Σ[(F_i + F_(i+1))/2 × (x_(i+1) - x_i)], summing the area under the force-displacement curve. This provides accurate results when force isn't constant—essential for realistic engineering calculations, spring systems, and experimental analysis.

References & Further Reading

Learn more about force, work, and power from these authoritative physics resources:

Disclaimer: This calculator provides educational estimates based on classical mechanics principles. For professional engineering applications, consult qualified engineers and refer to relevant industry standards.

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