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UV-Vis Converter: Wavelength, Energy, Frequency & Wavenumber

Convert between UV-Vis wavelength, photon energy, frequency, and wavenumber. Enter a value in any unit to see all equivalent values and identify the spectral region (UV-C, UV-B, UV-A, visible color, or near IR).

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Formulas verified by Abbas Kalim Khan, Associate Scientist

Enter UV-Vis Data

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Enter UV-Vis Data

Enter a wavelength, photon energy, frequency, or wavenumber to convert between common UV-Vis units and see which spectral region it falls into.

Core relationships:

E = hc/λ (photon energy)

ν = c/λ (frequency)

ṽ = 1/λ (wavenumber)

This is an educational UV-Vis helper based on simple formulas. It is not a safety calculator or a substitute for instrument calibration.

Wavelength (nm) ↔ Energy (eV, kJ/mol)

Photon energy and wavelength are reciprocals, scaled by hc. The Planck-Einstein relation E = hν = hc/λ says a 400 nm violet photon carries about 3.10 eV (or 299 kJ/mol when scaled by Avogadro's number), while a 700 nm red photon carries 1.77 eV. The factor hc = 1240 eV·nm is the only conversion to memorize for UV-Vis work. Frequency follows from the same equation as ν = c/λ, and wavenumber (cm⁻¹) is 10⁷/λ(nm). Every UV-Vis spectrum maps directly onto a ladder of electronic-transition energies.

The core relationship is E = hc/λ, where h = 6.626 × 10⁻³⁴ J·s and c = 2.998 × 10⁸ m/s. Plug in λ in meters and you get energy in joules per photon. For a single photon that's a tiny number, so chemists prefer eV (1 eV = 1.602 × 10⁻¹⁹ J) or kJ/mol (multiply single-photon energy by Avogadro's number, 6.022 × 10²³). A quick shortcut: E(eV) ≈ 1240 / λ(nm). Memorize that and you can estimate photon energies in your head during a lecture.

Common mistake: forgetting to convert nm to meters before plugging into E = hc/λ. If you leave λ in nanometers, your energy is off by a factor of 10⁹. The calculator handles unit conversion automatically, but on an exam you need to remember: 1 nm = 10⁻⁹ m. Also, energy and wavelength are inversely proportional—shorter wavelength means higher energy. UV photons carry more energy than visible light, which is why UV causes sunburn and visible light doesn't.

Frequency (Hz) ↔ Wavenumber (cm⁻¹)

Frequency (ν) and wavenumber (ν̃) are two ways to express the same information. Frequency in Hz tells you oscillations per second: ν = c / λ. Wavenumber in cm⁻¹ tells you waves per centimeter: ν̃ = 1 / λ(cm) = 10⁷ / λ(nm). IR spectroscopists live in wavenumber space, but UV-Vis people usually stick with nm or eV. Still, converting between them is routine when comparing data across techniques.

The relationship between frequency and wavenumber is straightforward: ν = c × ν̃, where c is in cm/s (2.998 × 10¹⁰ cm/s). Wavenumber is directly proportional to energy: E = hcν̃. This is why IR spectroscopists like wavenumber—it scales linearly with energy, unlike wavelength (which is inversely proportional). A peak at 1700 cm⁻¹ has exactly twice the energy of a peak at 850 cm⁻¹. That linear relationship makes comparing peak energies intuitive.

For UV-Vis work, visible light spans roughly 14,300–25,000 cm⁻¹ (700–400 nm). UV extends to about 100,000 cm⁻¹ (100 nm). If a paper reports an absorption at 22,200 cm⁻¹ and you need nm: λ = 10⁷ / 22,200 = 450 nm. That's blue light absorption, so the compound appears orange (complementary color).

Spectral Region Identification

Knowing which spectral region a wavelength falls in tells you what kind of transition you're looking at. UV photons (100–400 nm) have enough energy to promote electrons between molecular orbitals—π→π* and n→π* transitions in organic molecules, d→d transitions in metal complexes. Visible photons (400–700 nm) do the same but for smaller energy gaps, often in conjugated systems or transition metal compounds.

Near-IR (700–2500 nm) involves overtones and combination bands of molecular vibrations. Far-UV or vacuum UV (below 200 nm) is absorbed by atmospheric O₂ and N₂, so measurements require a vacuum or nitrogen purge—hence the name. Most teaching-lab UV-Vis spectrophotometers cover 190–1100 nm, with a deuterium lamp for UV and a tungsten-halogen lamp for visible/near-IR, switching around 340–380 nm.

UV-A/B/C and Visible Color Bands

The UV spectrum is subdivided by biological effect. UV-C (100–280 nm) is the most energetic and is used for germicidal sterilization—DNA absorbs strongly near 260 nm, and UV-C photons cause thymine dimers that kill microorganisms. Earth's ozone layer blocks solar UV-C completely. UV-B (280–315 nm) causes sunburn and is partially blocked by ozone. UV-A (315–400 nm) penetrates deeper into skin, causes tanning and aging, and passes through window glass.

In the visible range: violet (380–450 nm), blue (450–495 nm), green (495–570 nm), yellow (570–590 nm), orange (590–620 nm), red (620–750 nm). The color you see is the complement of the absorbed color. A solution absorbing at 450 nm (blue) appears orange. Absorbing at 580 nm (yellow) appears violet. This complementary relationship is critical for interpreting UV-Vis spectra of dyes, indicators, and metal complexes.

Exam pitfall: students confuse absorbed color with observed color. If a problem says "the solution is blue," it absorbs orange light (around 600 nm), not blue. The color wheel helps: draw the visible spectrum as a circle, and the complement is directly across.

Photon Energy Constants Used

Every conversion in this calculator traces back to three fundamental constants. Planck's constant: h = 6.626 × 10⁻³⁴ J·s. Speed of light: c = 2.998 × 10⁸ m/s. Avogadro's number: Nₐ = 6.022 × 10²³ mol⁻¹. From these you derive the conversion factor hc = 1.986 × 10⁻²⁵ J·m, or equivalently 1240 eV·nm.

Other useful derived values: 1 eV = 1.602 × 10⁻¹⁹ J = 96.485 kJ/mol = 8065.5 cm⁻¹. The Boltzmann constant kB = 1.381 × 10⁻²³ J/K gives thermal energy at room temperature: kBT ≈ 0.026 eV at 298 K. Comparing photon energy to kBT tells you whether a transition is thermally accessible. A 400 nm photon (3.1 eV) is 120× thermal energy—not thermally accessible, which is why electronic transitions require light, not heat.

Spectroscopy Q&A

Why do conjugated molecules absorb at longer wavelengths? More conjugation means a smaller HOMO-LUMO gap. Electrons delocalized over a larger π system need less energy to jump, so the absorption shifts to longer wavelengths (lower energy). This is why β-carotene (11 conjugated double bonds) absorbs blue-violet and appears orange, while ethylene (one double bond) absorbs in the far UV around 165 nm.

What's the difference between a nm and an Å in spectroscopy? 1 nm = 10 Å. Older literature and crystallography use Ångströms; modern UV-Vis spectroscopy uses nanometers. If a paper from the 1960s reports λmax = 4500 Å, that's 450 nm.

Can I convert wavelength to bond dissociation energy? Only roughly. The photon energy E = hc/λ gives the minimum energy to break a bond if the molecule dissociates upon absorption. But most absorptions lead to excited states, not dissociation. The actual bond energy depends on the potential energy surface, not just the absorption wavelength.

Why does my spectrophotometer cut off below 190 nm? Atmospheric oxygen absorbs strongly below 200 nm. Standard instruments use air paths, so they can't measure in the vacuum UV. Nitrogen-purged instruments extend to about 175 nm. Below that, you need a vacuum spectrometer or synchrotron radiation.

Planck-Based Conversion

• Wavelength → energy (J): E = hc / λ. Use λ in meters. h = 6.626 × 10⁻³⁴ J·s, c = 2.998 × 10⁸ m/s.

• Energy (eV) shortcut: E(eV) = 1240 / λ(nm). Fast, accurate to 4 significant figures.

• Energy (kJ/mol): E(kJ/mol) = E(J) × Nₐ / 1000 = 1.196 × 10⁵ / λ(nm).

• Wavelength → frequency: ν = c / λ. Use consistent units (m and m/s, or cm and cm/s).

• Wavelength → wavenumber: ν̃ = 1 / λ(cm) = 10⁷ / λ(nm). Units: cm⁻¹.

• Wavenumber → energy: E = hcν̃. Linear relationship: double the wavenumber, double the energy.

• Complementary color: Absorbed wavelength → color wheel opposite = observed color.

450 nm → eV Calculation

Problem: A compound has λmax = 450 nm. Convert this to energy in eV, kJ/mol, frequency in Hz, and wavenumber in cm⁻¹. Identify the absorbed color and predict the observed color.

Energy in eV:

E = 1240 / 450 = 2.756 eV

Energy in kJ/mol:

E = (6.626 × 10⁻³⁴)(2.998 × 10⁸) / (450 × 10⁻⁹)

E = 4.414 × 10⁻¹⁹ J per photon

E = (4.414 × 10⁻¹⁹)(6.022 × 10²³) / 1000

E = 265.8 kJ/mol

Frequency:

ν = c / λ = (2.998 × 10⁸) / (450 × 10⁻⁹)

ν = 6.662 × 10¹⁴ Hz

Wavenumber:

ν̃ = 10⁷ / 450 = 22,222 cm⁻¹

Color:

450 nm = blue light absorbed

Observed color = orange (complement of blue)

Cross-check: 2.756 eV × 96.485 kJ/(mol·eV) = 265.9 kJ/mol ✓. The slight rounding difference (265.8 vs. 265.9) comes from intermediate rounding—both are correct to 4 significant figures. At 265.8 kJ/mol, this photon energy is comparable to a C–Cl bond strength (~339 kJ/mol) but well below a C–H bond (~413 kJ/mol), which is why visible light doesn't break most organic bonds.

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Frequently Asked Questions

How do I convert wavelength to photon energy?
Use the equation E = hc/λ, where h is Planck's constant (6.626 × 10⁻³⁴ J·s), c is the speed of light (2.998 × 10⁸ m/s), and λ is wavelength in meters. For wavelength in nanometers (nm), a convenient approximation is: E(eV) ≈ 1240 / λ(nm). For example, for 500 nm light: E ≈ 1240 / 500 = 2.48 eV. For exact calculations: (1) Convert wavelength to meters (nm → m: multiply by 10⁻⁹), (2) Calculate E = hc/λ in joules, (3) Convert to eV if needed (1 eV = 1.602 × 10⁻¹⁹ J). That simple inverse relationship is why blue and UV photons carry more energy than red light.
What is the difference between UV-A, UV-B, and UV-C?
These are conventional divisions of ultraviolet light based on wavelength and biological effects. UV-C (~100–280 nm) is highest energy UV, germicidal, and absorbed by atmospheric ozone. UV-B (~280–315 nm) causes sunburn and vitamin D synthesis. UV-A (~315–400 nm) is lowest energy UV, used in 'black lights' and tanning, least harmful UV. These boundaries are approximate and vary slightly between references. The calculator automatically identifies which region a wavelength falls into.
Why do we sometimes use eV and sometimes kJ/mol?
eV (electron-volts) describes the energy of a single photon and is convenient for atomic/molecular scale discussions. Visible light is roughly 1.7–3.1 eV. kJ/mol describes the energy of Avogadro's number of photons (one mole) and is useful when comparing to bond energies or reaction enthalpies, which are typically given in kJ/mol. Visible light is roughly 170–300 kJ/mol. The conversion is: E(kJ/mol) = E(eV) × 96.485 kJ·mol⁻¹·eV⁻¹. For molar quantities (photons absorbed in moles, reaction energetics) kJ/mol matches the rest of the thermodynamic numbers. For single-photon work (semiconductor band gap, spectroscopic transitions) eV is the convention.
Why does shorter wavelength light have higher energy?
From E = hc/λ, energy is inversely proportional to wavelength. Shorter wavelength means more wave cycles fit in a given distance, corresponding to higher frequency (ν = c/λ) and higher energy (E = hν). This is a fundamental property of electromagnetic radiation: shorter wavelengths pack more energy into each photon. For example, violet light (~400 nm) has energy E ≈ 3.1 eV, while red light (~700 nm) has energy E ≈ 1.8 eV—violet has nearly twice the energy.
What is wavenumber and why is it used?
Wavenumber (ṽ) is the reciprocal of wavelength, typically expressed in cm⁻¹. It's proportional to energy and frequency, making it convenient for spectroscopy. IR spectroscopists often prefer wavenumber because it scales linearly with energy, unlike wavelength. For wavelength in nm: ṽ (cm⁻¹) ≈ 10⁷ / λ (nm). For example, 500 nm corresponds to ṽ ≈ 20,000 cm⁻¹. For IR work, peaks are reported in cm⁻¹ (C-H stretch around 2950, C=O stretch around 1700, O-H stretch broad near 3400). Direct comparison across spectra is easier in wavenumber than wavelength.
Why don't my results account for refractive index?
This tool assumes light travels in vacuum (n = 1) for simplicity. In a medium with refractive index n, the wavelength shortens to λ/n while frequency stays constant. For example, in glass (n ≈ 1.5), 500 nm light has wavelength ≈ 333 nm in the medium, but frequency (and energy per photon) stays the same. For most educational purposes and air/vacuum comparisons, this approximation is sufficient. Precise work in glass or solutions requires medium-specific calculations. For air and vacuum examples this shortcut is fine; for optics in real media, it is not the whole story.
What wavelength range do UV-Vis spectrophotometers cover?
Most laboratory UV-Vis instruments cover approximately 190–1100 nm, spanning UV-C through near IR. The exact range depends on the detector and light source. Below ~190 nm, atmospheric oxygen absorbs strongly, requiring vacuum UV techniques. The calculator covers wavelengths from ~100 nm to ~2500 nm for educational purposes.
How does visible light wavelength relate to color?
The visible spectrum (~400–700 nm) ranges from violet at short wavelengths to red at long wavelengths. Approximate color bands: violet 400–450 nm, blue 450–495 nm, green 495–570 nm, yellow 570–590 nm, orange 590–620 nm, red 620–700 nm. Perceived color depends on many factors including intensity, surrounding colors, and individual perception. Perceived color depends on the spectral mix as well as the dominant wavelength. A 580 nm monochromatic source looks the same yellow as a balanced red+green mixture whose intensity-weighted centroid sits near 580 nm. The calculator shows approximate colors for visible wavelengths.